A body whose moment of inertia is 3 kg-m 2 is in rest. It is rotated for 20 sec by a torque of 6 Nm, angular displacement of the body will be :
Text Solution
Verified by ExpertsThe correct answer is:
A
λ = 3 kg m 2 , τ = 6 Nm, t = 20 sec
From τ = I α
Angular accleration 
= 2 rad/sec 2
∴ Angular displacement
= 
= 0 × 20 + 
(20) 2
= 400 radian
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